12 islanders seesaw riddle answerdescribe the features of an evacuation plan floral design
Its similar to a puzzle about pool balls I put in my math brain teasers list a few years back but way harder. Otherwise the one who stayed is the oddly weighted one. Happy problem solving. Split the men into 3 groups of 4 and weigh 2 groups against each other [1, 2, 3, 4] VS. [5, 6, 7, 8]. Start off by weighing 4 against 4, setting the other 4 aside completely. put A&B on the seesaw then put A&C ( 2 uses) logic will give you the answer. Thus in principle we can get log 2 27 bits from the three comparisons. The exciting catch? Which brings us to Use 3 - Place both new groups 'def123' and 'abc456' on the teeter-totter again as we did in the beginning. The riddle: There are 12 islanders on an island. Use Git or checkout with SVN using the web URL. Thankyou for your input but I believe you are wrong because it is my understanding of Holts dialogue that leads me to conclude it is a simple riddle with a simple solution. You signed in with another tab or window. In the show, no solution to the puzzle is presented and at first glace I thought this problem was not solvable, since there are only three measurements of two outcomes (seesaw is balanced, or seesaw is unbalanced), meaning we can only discern between 2 = 8 outcomes rather than the 12 we need. we now know that the odd islander is S4. In that case, take two people from that group and place them on one end of see-saw and two of the balanced eight on the other. Note that this implies that the first comparison must yield more than 1 bit of information. The island has no scales but there is a see-saw. (Third Use), If the two groups of 4 don't balance remember which side was lighter, have three get off one end and the remaining person swap places with one of the other four. {{3 remaining with known weight solution}} Since the weight is known, all you need to do is measure 2 men from the remaining 3 against each other. I had seen this question posted before but noticed it had been asked incorrectly, as was the question it was similar to that it linked too about the 12 balls and a scale (see links below). If the seesaw balances we know that either 1 or 2 or 3 is oddly weighted. Use the weight difference from step 1 to determine heavier lighter. If they are equal then Weigh 9, 10, 11 vs 1, 2, 3. Comparing (1,2,3,4) to (5,6,7,8) does exactly this. Solution 2c. Stack Exchange network consists of 181 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers. The following steps become identical to those in Scenario 1., above. You must figure out which. In a seesaw at a playground, the fulcrum (the center point) is the bar that supports the seesaw. A seesaw is binary. 2.B.1 if left heavy one side was lighter and is now heavier) then you know it was one of the 3 men who changed sides from the left to the right. There is an island with 12 islanders. There are no scales or other weighing device on the island. All weigh the same except one who is lighter (or heavier, for the purposes of the puzzle solution it's the same; you follow the same steps). The odd man is in the group is in 9-12. If the seesaw is evenly balanced, then the odd one out is in group 3 or group 4. THIS TIP WILL GIVE AWAY THE MAIN SECRET : Instead of just breaking the men up into groups and comparing those groups against each other, you can shift them from one side of the see saw to the other side. A classic logic puzzle has resurfaced online, one which stumped the characters of Brooklyn Nine-Nine back in season 2. Are you sure you want to create this branch? What is the answer to the seesaw riddle? Number the men from 1 to 12. I believe it was in. now compare L2 and L3. Three measurements in all. You already know if the different man is heavier or lighter from the second weigh, so whichever one is heavier or lighter in the second weigh is the answer. There is also a see-saw on the island. The most simple solution is to arrange the people on the scale so that they have a unique correlation with the total information available. In step 3 place one unknown on each side. You cant solve this puzzle? Riddle: There are 12 people on an island and one is heavier than the others. The first measurement of 4 vs. 4 was equal. Say as example 1234 were lighter. Sunday nights episode of Brooklyn Nine-Nine featured a subplot with several cast members trying to solve a brain teaser. I was lying there going through possibilities until 3 am when it hit me, and I got up and wrote down the solution. (seesaw measurement number 3), 2.A.2 if left is heavy Weigh them against each other. The riddle 12 men live on an island. You signed in with another tab or window. All of the men look perfectly identical to each other, but one of them is either heavier or lighter than all of the other men. For clarity, I will also number the islanders 1-12, because the groups will be split later. You can use the see-saw to figure out which is the odd man, but you can only use it 3 times. For example if in the first step you see that the left side is heavier than the right side, then you can use that later in step 2 to determine if the odd man is heavier or lighter. sideline: S1 S2 S3 S4, 2.A.1 if balanced And there's another twist: you're only allowed to use the see-saw three times. There are 12 men on an island. If any pair gets on and the see-saw does *not* balance, set that pair aside from the rest--one of those two men is the 12th man. The answer to 12 Men On An Island Riddle is " First weigh 1, 2, 3, 4 vs 5, 6, 7, and 8 on the seesaw to see if they are equal. 12 men live on an island. now switch R1 R2 R3 and S2 S3 S4 AND switch R1 AND L1. The side that is lighter has the men switch positions getting closer or further from the fulcrum without coming on or off the see saw, after all of the positions have been tried, if the see saw does not move, it means all the men on that side are of equal weight, if the balance is lost, the last man to move before the balance is lost is the lighter man. Thus in principle we can get log227 bits from the three comparisons. (Second Use). And if they are, then weigh 9, 10, 11 vs 1, 2, and 3. Proceed to step 2. Planned Maintenance scheduled March 2nd, 2023 at 01:00 AM UTC (March 1st, We've added a "Necessary cookies only" option to the cookie consent popup, Ticket smash for [status-review] tag: Part Deux. [9, 10, 11] VS. [1, 2, 3]. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. If one is heavier they are the odd one otherwise it is 6. How do you do it? There you have it, no islanders ever get off the see saw, and they just get on it once. Weigh A against B. Take 3 men from the group and measure against 3 neutral men from 1-8. You must figure out which. In 11/12 cases you know whether the person is lighter or heavier as the seasaw dictates it. 12 Islanders Riddle Puzzle from Brooklyn 99. c) If they are the same, then one of 3,4 is different. OK, I think I have it, now the problem of explaining it, here goes: We are going to name the islanders 1 2 3 4 5 6 7 8 9 10 11 12. Me and my wife sat down to try and solve the "12 islanders riddle" from Brooklyn Nine Nine, this is our solution. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. Puzzling Stack Exchange is a question and answer site for those who create, solve, and study puzzles. @emdee - Here is the link that you posted in the question. if balanced it is S3 - else it is the lighter of S1 and S2. Puzzling Stack Exchange is a question and answer site for those who create, solve, and study puzzles. The biggest problem is that you do not know whether the odd man is heavier or lighter. seesaw: R1 L2 L3 L4 L1 S2 S3 S4 (balanced) IF the scale is unequal, then you know the odd man is within the group 8-11. if balanced it is L4 - else it is the heavier of L2 and L3. if balanced it is R4 - else it is the lighter of R3 and R2 You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. Each islander is given a position to sit on the seesaw for each round. And there you have it! Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site. Find out the minimum number of times the seesaw will be used. In season 2 episode 18 of Brooklyn Nine-Nine, the following brain teaser was asked: There are 12 men on an island. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. (Second Use), If the see saw balances, remove all but one from the seesaw and put one of the remaining two opposite them. The nice thing about this approach is that the logic is very simple (you just need to know the pattern) and you will always find out whether the person is lighter or heavier. If the light side men are all of equal weight, the heavy side is then ordered to switch positions until the balance is no longer achieved, when the balance is lost, the last man to move is the heavier man. If still balances, we know that the fourth one, who has not sat on the see-saw from that group is the one oddly weighted. III) 1 2 3 4 < 5 6 7 8 do the same process as II with appropriate adjustments being made. 11 weigh exactly the same amount, but one of them is slightly lighter or heavier. Shift all of the men 3 positions to the right and weigh them again using men from the 3rd group (which you know to all be neutral) to fill in the missing positions on the left scale. You must figure out which. Fun: (2.49) Difficulty: (1.28) Puzzle ID: #13528 Submitted By: cool_star. Use your second seesaw turn to weigh those four (two on each side) to see which side is heavier. Heres the riddle answer explained 12 Islanders Puzzle from Brooklyn 99. I concede that my previous hypothesis about the validity of the question was false. IF the 2 scales are unequal, then you know the odd man is in the set of 1-8. sideline: S1 S2 S3 S4 (Third Use), If the see saw is not balanced, remove one from each end. I am just looking for a little tweak to this answer. If nothing happens, download GitHub Desktop and try again. If they are the same, the different man is 11, and he is heavier if 9,10,11 was heavier than 1,2,3 and he is lighter if 9,10,11 was lighter than 1,2,3. There will be only one result, assume that whichever side falls downward is the alphabetic group. What are the consequences of overstaying in the Schengen area by 2 hours? Let's say 'abc' and '456'. Similar logic will help us design all further comparisons. @Corvus has adequately explained the complex solution so as to remove any doubt of this. So in principle, we should be able to solve the problem. The best answers are voted up and rise to the top, Not the answer you're looking for? Weigh 9, 10, 11 vs 1, 2, 3. Your aim is to find out which person weighs a different amount. If they are equal, it is the remaining man not being measured. Thanks, AeJey for making it so clear! Split the men into two(2) groups 'abcdef' and '123456'. Eleven weigh exactly the same amount, but one of them is slightly lighter or heavier. You have to figure out which Islander is the heaviest using a seesaw. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. The kid sitting on the end is the load. See our massive list below, or chat to other parents in our forum. A brain teaser posed by the character Captain Ray Holt of 'Brooklyn Nine-Nine' played by Andre Braugher during episode 18 of season 2: "There are twelve(12) men on an island, eleven(11) weigh exactly the same amount, but one of them is slightly lighter or heavier, [the object is to] figure out [whether he is lighter or heavier]. Eleven weigh exactly the same amount, but one of them is slightly lighter or heavier. You can only use it three times.. Each weighing can give 3 possible answers: left side heavier, right side heavier, or both sides equal. If they are equal then. Weigh 9,10,11 against 1,2,3. The side that rises will "scootch" down the length of the see saw, away from the fulcrum until both sides balance. 2150 Condos - West Tower Phase 2 seesaw: S1 S2 S3 R1 R2 R3 (heavy) Set it up so deduction eliminates everything else and your gold. Can patents be featured/explained in a youtube video i.e. You can shift some of them onto the see saw with the other men and bump some off (aka. There are no scales or other weighing device on the island. Scenario Two, from your original 4x4 weighing: 2. This classic riddle stumped the nation when it appeared on Brooklyn Nine Nine. Each islander is given a position to sit on the seesaw for each round. In other news,did Pete Davidson tattoo a kid? sideline: L1 L2 L3 S4 L4 R4 (Third Use)notethis works equally well if the group was lighter, just replace terms for appropriate identification. The See-Saw. Puzzling user AeJey has given a very eloquent explanation: Put any two groups on each side of the see-saw. Are you sure you want to create this branch? There is also a see-saw on the island. 2150 Condos - West Tower Phase 2. New post because the last one got too old. Example for condition 1: put three "unknowns" against three "knowns". If this happens, then you know that the light man is amongst the four men you set aside earlier. Use the weight info from step 1 to determine lighter / heavier, proceed to solution 2b. There are 12 men on an island. If nothing happens, download Xcode and try again. Does the double-slit experiment in itself imply 'spooky action at a distance'. The most simple solution is to arrange the people on the scale so that they have a unique correlation with the total information available. At this point we just weight S4 against a This way of wording will help make it easier to figure out the puzzle. (seesaw measurement number 3), 2.B.2 if balanced (seesaw measurement number 3), 2.B.3 if right heavy There are 27 total permutations for the position of the scale which easily leaves you a symmetric configuration that allows you to determine which person it is and whether they are heavy or light every time. Is it possible to measure 1 kilogram of sugar? Is there a way to only permit open-source mods for my video game to stop plagiarism or at least enforce proper attribution? Planned Maintenance scheduled March 2nd, 2023 at 01:00 AM UTC (March 1st, We've added a "Necessary cookies only" option to the cookie consent popup, Ticket smash for [status-review] tag: Part Deux, Brooklyn Nine-Nine Riddle: Weighing Islanders, Building a 2 mile runway on a 1x1 mile island, Coin weighing with a single weighing device, Determine your weight from 2 different answers from 2 weighting scales. Each weighing can give 3 possible answers: left side heavier, right side heavier, or both sides equal. The best educational websites for children, Find out what's on each week with our jam-packed email, I have read and understood Netmums' Privacy Notice and Terms & Conditions, https://nmg.netmums.com/header/activities/, https://www.netmums.com/esi/video/false/position:ATF, https://www.netmums.com/esi/mostactivechat/website/article. sideline: S1 S2 S3 S4. Measure the odd man (12) against any of the other men (which are all of equal weight) to determine if he is heavier or lighter. sideline: S4 L1 L2 L3 L4 R4 Solution 1a. Just forget about them for a few minutes. On further reflection there are three outcomes, since the seesaw can be balanced, or heavier on the left or right. (named after their starting position, L1 = Left 1, R1 = Right 1, S1 = Side 1 etc..), We now know that the odd islander are amongst S1 S2 S3 S4 If they 9 vs 10 is balanced, then you can deduce that the 11th islander is the different weight. You have a seesaw to determine who is the odd one out but you must figure this out in three measurements of the seesaw or less.. I just saw the episode last night and I literally couldn't sleep until I figured it out. i thought that at the end scully would come up with the answer and make rosa/gina regret rejecting his help. Jordan's line about intimate parties in The Great Gatsby? Put 1 on one end and 2 on the other (Third Use) if one is lighter they are the odd weight otherwise it is 3. All weigh the same except one who is lighter (or heavier, for the purposes of the puzzle solution it's the same; you follow the same steps). Put any two groups on each side of the see-saw. Jordan's line about intimate parties in The Great Gatsby? (Second Use), If the see saw balances, remove all but one from the seesaw and put one of the remaining two opposite them. If the 9,10,11 differs from 1,2,3, then weigh 9 against 10. Press question mark to learn the rest of the keyboard shortcuts. First weigh 1,2,3,4 against 5,6,7,8. One problem - you have to figure out which person it is too. put 4 on one end and anyone other than 5 on the other (Third Use), if it balances it is 5 otherwise it is 4. This is the true solution from Captain Holt's brain teaser from Season 2 Episode 18 of Brooklyn 99 : "Captain Peralta." Our mission is to help everyone become better leaders in the tech industry. There was a problem preparing your codespace, please try again. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. If the seesaw reverses, ether 4 or 5 is the oddly weighted one. If balanced it is the heavy L1 else if unbalanced it is light R1. No Scenarios, No Cases, Just The Simple Answer.Instagram: https://www.instagram.com/lifeprojxFacebook: https://www.facebook.com/lifeprojx The essence of the riddle is: "There are 12 men on an island. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. Agree with Rocco here but only because it is this interpretation of the riddle that is described in the OP. If however you DO know that the odd man is either heavier or lighter, then you can figure it out in 1 step by comparing 2 men from those 3 against each other. Number the men 1,2,312. Software Engineer Author has 67 answers and 176.2K answer views 3 y Number each of the 12 people from 1 through 12. Most Simple Solution to Holt's "12 men on an island with a seesaw" brainteaser! rev2023.3.1.43268. Note : I am not looking for a new way to solve this. 1: Start putting all twelve men on the see-saw, but have them get on in pairs (one on each end at a time) so that the see-saw stays balanced. 11 of them weigh the same and one of them is either slightly heavier or slightly lighter. Now, weigh the remaining eight men on the seesaw, four on each side. now compare R2 and R3. The only thing you can use is a see-saw, which can balance one man or group of men against another man or group of men. What are some tools or methods I can purchase to trace a water leak? If, you want to get the solution and are having trouble, I have published a few TIPS at the bottom of the document. run a simulation: go run . heavier or slightly lighter. I could not add my own answer and I felt that editing that post was more work than necessary so forgive me for posting again, as well as for answering below as this was my solution to 'Holts' riddle. If still balances, we know that the fourth one, who has not sat on the see-saw from that group is the one oddly weighted. If they are equal then. seesaw: R1 L2 L3 L4 (heavy) L1 S2 S3 S4 11 of them weigh the same and one of them is either slightly heavier or slightly lighter. It is a good write up though. Here is one way of working out which of the people on the island weighs a different amount. You must figure out which. b) If 1,2,5,6,7 is lighter, then one of 5,6,7 is different and lighter. [10, 11, 12, 1] VS. [2, 3, 4, 5]. Create an account to follow your favorite communities and start taking part in conversations. How do you do it? This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. It is impossible to know both for sure in only three steps.). It only takes a minute to sign up. Thanks! 12 Islanders Teeter Totter Riddle There is an island with 12 islanders. That person is the heavier (or lighter). (First Use). I wonder if this is the highest-viewed duplicate question of all time? PTIJ Should we be afraid of Artificial Intelligence? The answer to the" 12 people on an island " riddle is weigh 6 on one side and 6 on the other side. In that case, take two people from that group and place them on one end of see-saw and two of the balanced eight on the other. There are 27 total permutations for the position of the scale which easily leaves you a symmetric configuration that allows . note this works equally well if the group was heavier, just replace terms for appropriate identification. That's not true. 11 weigh exactly the same amount, but one of them is slightly lighter or heavier. I like Rosa's answer squeeze until fatty confesses. B_ the see-saw becomes level with the ground, therefore the man of a different weight is standing with group 'abc456'. we weigh S1 against S2. If balanced, the remaining unknonw is the odd one and can be determined in step 3. Now we know that the different man is among {9,10,11,12}. It is easier than everyone makes it. 1 v 12). Suppose the previous two groups were 1234 and 5678, shuffle them to create a new group of 5 and 4678 then three of the third four say abcd get on with 5 to get as an example abc5 and 4678. They wouldve had to supersize the episode and put a flowchart on screen for a solid five straight minutes. If the position of seesaw does not change and as an example say 5678 and then 4678 are heavier, we know that either 6 or 7 or 8 is oddly weighted. seesaw: L1 L2 L3 L4 R1 R2 R3 R4 If they are different, the lighter of the two is the one we are looking for (and lighter). Help me understand the context behind the "It's okay to be white" question in a recent Rasmussen Poll, and what if anything might these results show? 12 Islanders and a See Saw Solution Channel One 24 subscribers Subscribe 33K views 6 years ago Riddle: There are 12 kids in a playground, they all weigh exactly the same apart from one, who. Questions: In this way, x can be found, no matter which islander it is, as all 12 have a test to find an answer for. we know it is either R1 or L1. Why are non-Western countries siding with China in the UN? The unique and extremely popular [citation needed] authority on pop culture since 2008. The exciting catch? You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. Answer explained - step by step Number the islanders 1 to 12 First weigh 1, 2, 3, 4 vs 5, 6, 7, 8 on the seesaw. Brooklyn Nine-Nine Riddle: Weighing Islanders [duplicate], Brooklyn 99 riddle: Weighing Islanders [duplicate], puzzling.stackexchange.com/questions/9979/, puzzling.stackexchange.com/questions/183/. One of two things will happen: The seesaw will be perfectly balanced. 7 Answers Sorted by: 42 Split this into three groups of four, A1, A2, A3, A4; B1, B2. Here is a more precise retelling of the riddle we found. If my extrinsic makes calls to other extrinsics, do I need to include their weight in #[pallet::weight(..)]? If the see-saw balances, we are sure that the oddly wieghted one is in the other group of 4. Hope you all sleep well after reading this. Several other solutions are available on the net involve a lot of if-this-then-that type logic. Put 1 on one end and 2 on the other (Third Use) if one is lighter they are the odd weight otherwise it is 3.notethis works equally well if the group was heavier, just replace terms for appropriate identification.'. {{#media.media_details}} {{#media.focal_point}}, First weigh 1, 2, 3, 4 vs 5, 6, 7, 8 on the seesaw. However only three measurements are allowed. Bottom line? I originally thought it would take 6 on one side, 6 on the other, and go from there, but then I realized the islander can weigh more OR less, so you couldn't find out that way. There are 12 men on an island. You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. There is an island with 12 islanders. If these are equal, the different man is 12. The only case where you dont is 1.1.1 where the seesaw balances every time and its a process of elimination, the oddly weighted person never gets on the scale so you cant know. (Detailed . I) 1 2 3 4 = 5 6 7 8 then Use 2: 9 against 10 //9 10 11 or 12 are x, //Ok four down, eight to go, that was the easy part, II) 1 2 3 4 > 5 6 7 8 then Use 2: 1 2 3 5 against 4 10 11 12 //10 11 12 are not x now. If the seesaw reverses, ether 4 or 5 is the oddly weighted one. If he is lighter then it is the one being measured and he is lighter. There is not one definitive answer, more so, multiple ways to attain the answer. Can you solve the classic 12 marbles riddle? The seesaw will balance perfectly. How does a fan in a turbofan engine suck air in? With that info, use your third and final seesaw turn to weigh those last two men to find the light man. "There are 12 men on an island. Please 12K views, 12 likes, 0 loves, 42 comments, 1 shares, Facebook Watch Videos from Adventure Rooms Adelaide - Escape Rooms and Bar: Can you solve the 12 Islanders Riddle and help them escape safely?. (Third Use) 11 weigh exactly the same amount, but one of them is slightly lighter or heavier. All our articles and reviews are written independently by the Netmums editorial team. Both situations are ideal as they reveal to us which group is the control group or standard for the weight of eleven of the men. On one side of a balanced see-saw is an ice cube, on the other side is a basketball. Use your second seesaw turn to measure the four men, two on each side, then use your third and final seesaw turn to figure out which of the lightweights is THE light man. Presented below is a simpler solution. Now you know that one of the four men on one side is light. Learn more about Stack Overflow the company, and our products. Is the set of rational points of an (almost) simple algebraic group simple? How is "He who Remains" different from "Kang the Conqueror"? Now put 7 on one end and 8 on the other. Have something to tell us about this article? Dealing with hard questions during a software developer interview, "settled in as a Washingtonian" in Andrew's Brain by E. L. Doctorow. (seesaw measurement number 3), 2.A.3 if right is heavy If they are the same, 7 is different (and lighter). Problem solved. There are 12 men on an island. Thats really not conducive to Andy Samberg zingers. Connect and share knowledge within a single location that is structured and easy to search. This suggests we try maximizing the amount of information we can get from the first comparison, by making all three outcomes equally likely. If the see saw is not balanced, remove one from each end. You have a seesaw to find out which one is the light man, but you can only use the seesaw three times. Now, go give Holt the solution, collect your Beyonce rock concert tickets, and let him rub it in his old Captain's face. Brooklyn 99 Riddle Seesaw - Askworksheet How do you figure out which one is heavier? All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. Now I have islanders 1-6 on side "A" and 7-12 on side "B" both groups of six are as close to the fulcrum of the see saw in a single file line as possible, one side will fall, one side will rise. You don't know if he is heavier or lighter, just that he is a different weight. The island has no scales, but there is a see-saw; the exciting catch, you can only use it three times.". I gave each of the 12 men a letter, A-L. Can You Solve the Brain Teaser of the 12 Men and a See-Saw? Are there basic weighing puzzles requiring adaptive strategies? You can weigh three combinations of men on the see-saw. seesaw: L1 L2 L3 L4 R1 R2 R3 R4 (balanced) You still have 1 remaining move and you now know if the odd man is heavier or lighter. :D, Brooklyn 99 riddle: Weighing Islanders [duplicate]. Wow how did this even get 8 upvotesmind boggling. Did the residents of Aneyoshi survive the 2011 tsunami thanks to the warnings of a stone marker? Solution 2b. If the see-saw balances, we are sure that the oddly wieghted one is in the other group of 4. Weigh the lighter of the 2 men against any other neutral man. Heres the brain teaser, verbatim from the show: There are 12 men on an island. The island has no escapes, but there is a see-saw. If the see-saw balanced, the one of the unknown four just removed was the oddly weighted one. Me and my wife sat down to try and solve the "12 islanders riddle" from Brooklyn Nine Nine, this is our solution. Use the {{3 remaining with known weight solution}} from solution 1a. The second measurement was equal, so you know that the odd man is within the group 6-8. The seesaw will NOT be perfectly balanced. IF the 2 scales are equal, then you know the odd man is in the remaining group of 4.
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